Let's denote the measures of the angles as follows:
Let �A be the measure of the first angle. Let �B be the measure of the second angle. Let �C be the measure of the third angle.
According to the problem:
- �=2�−20B=2A−20 (One angle is 20 degrees less than twice the measure of another angle).
- �=�+30C=A+30 (The third angle is 30 degrees more than the first angle).
We also know that the sum of the angles in a triangle is always 180 degrees. Therefore:
�+�+�=180A+B+C=180
Now, substitute the expressions for �B and �C from the first two equations into the third equation:
�+(2�−20)+(�+30)=180A+(2A−20)+(A+30)=180
Combine like terms:
4�+10=1804A+10=180
Subtract 10 from both sides:
4�=1704A=170
Divide by 4:
�=42.5A=42.5
Now that we know �A, we can find �B and �C:
�=2×42.5−20=85−20=65B=2×42.5−20=85−20=65
�=42.5+30=72.5C=42.5+30=72.5
So, the measures of the three angles in the triangle are 42.5∘,65∘, and 72.5∘